H3 MATHEMATICS · MATHEMATICAL INDUCTION

Anchor the first case.
Then build the logical bridge.

A proof-writing guide for Singapore A-Level H3 Mathematics syllabus 9820. State the proposition precisely, use the induction hypothesis visibly and close the argument for every required integer.

  • Precise propositions
  • Valid inductive steps
  • Complete conclusions
Dominoes representing an induction proofA base domino starts a chain, and a highlighted bridge connects the kth to the k plus first case.baseP(k)P(k+1)
01Both links matter Prove the first case and prove that any true kth case forces the next.
Built around 9820 H3 MathematicsProof by mathematical induction and rigorous mathematical argument
A chain, not a patternThe inductive step must logically use P(k) to establish P(k+1)

THE LOGICAL ENGINE

Base case plus implication

Checking several cases can suggest a statement, but it cannot prove infinitely many cases. Induction combines one verified starting point with a universal implication.

The induction hypothesis is temporary and conditional: assume P(k) for an arbitrary valid k, then use it to prove P(k+1).

THE PROOF FRAME

Make every logical link visible

01

Define P(n)

State exactly what is to be proved and its integer domain.

P(n):the stated identity holds
02

Verify the base

Substitute the first required value on both sides.

P(1)
03

Assume P(k)

Take an arbitrary k in the domain and state the hypothesis.

P(k) is true
04

Prove P(k+1)

Transform the next case, explicitly invoking the hypothesis.

P(k)P(k+1)

WORKED EXAMPLE

Prove the sum of the first n odd integers.

Prove by induction that 1+3++(2n1)=n2 for every positive integer n.

EXAM HABIT

In the next case, append the new term; do not replace the whole sum without explanation.

  1. 1

    Base case n=1

    LHS=1=12=RHS

    So P(1) is true.

  2. 2

    Induction hypothesis

    Assume for some positive integer k that

    1+3++(2k1)=k2
  3. 3

    Build the next case

    k2+[2(k+1)1]=k2+2k+1=(k+1)2
  4. 4

    Conclude

    Thus P(k) implies P(k+1). Since P(1) is true, the statement holds for all positive integers n by mathematical induction.

Proved1 + 3 + ⋯ + (2n − 1) = n² for all positive integers n.

COMMON MISTAKES

What to catch before the examiner does

01

Checking examples only

Several true cases suggest a result but do not prove all later cases.

02

Assuming P(k+1)

The induction hypothesis is P(k); P(k+1) is what must be established.

03

Not using the hypothesis

The inductive step must visibly depend on the assumed kth case.

04

Incomplete conclusion

Name the domain and invoke mathematical induction after proving both links.

PRACTISE WITH FEEDBACK

Have the logic—not only the algebra—checked.

Integrand can identify a missing base case, circular reasoning or an unused hypothesis.

Try Integrand
  1. 1

    State

    Define P(n) and its domain.

  2. 2

    Bridge

    Use P(k) to prove P(k+1).

  3. 3

    Conclude

    Invoke induction precisely.

QUICK QUESTIONS

H3 mathematical induction FAQ

Why is the base case necessary?

The implication P(k)⇒P(k+1) can propagate truth only after at least one valid starting case has been established.

Can I assume the result for every k?

Assume it for an arbitrary k in the stated domain, only for the purpose of proving the next case.

Is this guide within the H3 syllabus?

Yes. Proof by mathematical induction is included in Singapore A-Level H3 Mathematics syllabus 9820.

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READY TO PRACTISE?

Write the proof. Get feedback on every logical link.

Open Integrand